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In the diagram, square ABCD has side length 3.  Find the area of triangle PDQ.

 

 Jun 4, 2024
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angle ABP + angle BPA  = 90

angle DPQ + angleBPA = 90

 

So

angle ABP  =  angle DPQ

 

tan ABP  = 1/3

 

So  tan DPQ  = 1/3

 

So 

 

 1/3 = DQ/2

 

DQ = (2/3)

 

So

 

[ PDQ ]  =  (1/2) PD * DQ  =  (1/2) (2) (2/3)  =  2/3

 

cool cool cool

 Jun 5, 2024

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