+1855 We have a triangle $\triangle ABC$ and a point $K$ on $BC$ such that $AK$ is an altitude to $\triangle ABC$. If $AC = 8,$ $BK = 2$, and $CK = 3,$ then what is $AB$?
+1946 Since AK is the altitude, so we can use the pythaogrean thereom.
We have'
AK=√AC2−CK2=√82−32=√55AB=√AK2+BK2=√55+4=√59
Thanks! :)
