Find the area of an isosceles triangle with two legs of length 8 and base of length \(4\).
I will use the theorem called Heron's Fomula.
s = 10
\(\sqrt{10\left(10-8\right)\left(10-8\right)\left(10-4\right)}\)
=\(4\sqrt{15}u^2\)
+218 
