In triangle ABC, point X is on side BC such that AX=13,BX=10,CX=10, and the circumcircles of triangles ABX and ACX have the same radius. Find the area of triangle ABC.
Find the area of triangle ABC.
Point X is on side BC.AX=13, BX=10, CX=10△XAB symmetrical △XACAABC=12⋅(10+10)⋅13=130