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In triangle ABC, point X is on side BC such that AX=13,BX=10,CX=10, and the circumcircles of triangles ABX and ACX have the same radius. Find the area of triangle ABC.

 Apr 13, 2024
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Find the area of triangle ABC.

 

\(Point\ X\ is\ on\ side\ BC.\\ AX=13,\ BX=10,\ CX=10\\ \triangle XAB\ symmetrical\ \triangle XAC \\ \color{blue}A_{ABC}= \dfrac{1}{2}\cdot (10+10)\cdot 13=130\)

 Apr 13, 2024

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