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Points $A$, $B$, and $C$ are on a circle such that $AB = 8$, $BC = 15$, and $AC = 12$. Find the radius of the circle.

 Apr 11, 2024
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we can notice that 8, 12, and 15 are pythagorean triples, so the points A,B, and C form a right triangle ABC. Since ABC is inscribed in the circle, we know that its hypoteneuse, 15, is the diameter of the circle.

 

Therefore, \(\boxed{15/2}\) is the radius of the circle.

 Apr 11, 2024
edited by Mather459  Apr 11, 2024
edited by Mather459  Apr 11, 2024

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