The trapezoid shown has a height of length 12 cm, a base of length 16 cm, and an area of 180 cm^2. What is the perimeter of the trapezoid?
What is the perimeter of the trapezoid?
Helo Guest!
\(A=\frac{h(a+b)}{2}\\ b= \frac{2A}{h}-a=\frac{2\cdot 180cm^2}{12cm}-16cm\)
\(b=14cm\)
\(P=a+b+h+\sqrt{h^2+(a-b)^2}=(14+16+12+\sqrt{12^2+(16-14)^2})cm\)
\(P=54.17cm\)
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