In the diagram below, we have $AB = 24$ and $\angle ADB =90^\circ$. If $\sin A = \frac13$ and $\sin C = \frac12$, then what is $BC$?
sin A = BD / AB = BD / 24 = 1/3 → BD = 8
sin C = BD / BC = 8 / BC = 1 / 2 → BC = 16
+613 
