Two sides of an isosceles triangle are 10 inches and \(28\) inches. What is the area of the triangle?
+128408 By the triangle inequality, the equal sides must be 28 and the base = 10
[ If the sides were 10, their sum would be less than 28 ]
The height = sqrt (28^2 - ( base length / 2 )^2 ] = sqrt [ 784 - (5)^2 ] = sqrt [ 784 - 25 ] =
sqrt [ 759 ]
The area = (1/2)(10) sqrt [ 759 ] = 5 sqrt [ 759 ] ≈ 137.75 units^2
