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Let abc be a triangle and d be a point on ac such that ab = bd = cd. given that angle bac is \(76\) degrees, find angle abc

 Jan 15, 2022
 #1
avatar+23183 
+1

angle(ADB) = angle(BAC)  =  76

angle(BDC) = 180 - angle(ADB) = 180 - 76 = 104

angle(DCB) = angle(DBC) = (180 - 104)/2 = 38

angle(ABD = 180 - 76 - 76 = 28

angle(ABC) = 28 + 38 = 66

 Jan 15, 2022
 #2
avatar+360 
+1

its basically 2 iscoceles triangles if think about it, so if bac=76, then abd=180=152=28 

bdc=180-76=104 

dbc=180-104=76 76/2=38

28+38=66

 Jan 15, 2022
 #3
avatar+360 
0

and geno was literally 8 seconds before me!

 Jan 15, 2022

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