Let abc be a triangle and d be a point on ac such that ab = bd = cd. given that angle bac is \(76\) degrees, find angle abc
+23246 angle(ADB) = angle(BAC) = 76
angle(BDC) = 180 - angle(ADB) = 180 - 76 = 104
angle(DCB) = angle(DBC) = (180 - 104)/2 = 38
angle(ABD = 180 - 76 - 76 = 28
angle(ABC) = 28 + 38 = 66
+363 its basically 2 iscoceles triangles if think about it, so if bac=76, then abd=180=152=28
bdc=180-76=104
dbc=180-104=76 76/2=38
28+38=66
