Let AB be a diameter of a circle centered at O. Let E be a point on the circle, and let the tangent at B intersect the tangent at E and AE at C and D, respectively. If angle BAE = 41 degrees, find angle CED, in degrees.
find angle CED.
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AEO = 41° AOE = 98° BOE = 82°
ECD = 82° ADB = 49° CED = 49°
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