+802 The area of a trapezoid is $80$. The length of one base is $16$ units greater than the other base, and one base of the trapezoid is $12$. Find the length of the median of the trapezoid.
+10 \(A=80\)
\(B_1=12\)
\(B_2=B_1+16=28\)
\(Median=\frac{B_1+B_2}{2}=14\)
The length of the median of this trapezoid is equivalent to 14 units.
