In triangle ABC, AB = 15, BC = 20, and AC = 20. Find the length of the shortest altitude in this triangle.
Acute isosceles triangle.
Sides: a = 20 b = 20 c = 15 Area: T = 139.054 Perimeter: p = 55 Semi-perimeter: s = 27.5
Height: ha = 13.905 Height: hb = 13.905 Height: hc = 18.54