If a triangle has an area of 6 feet square and the base of the triangle is 6 feet, what are the lengths of the other sides of the triangle, and what is that triangle’s perimeter approximately?
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If a triangle has an area of 6 feet square and the base of the triangle is 6 feet, what are the
lengths of the other sides of the triangle, and what is that triangle’s perimeter approximately?
The second easiest solution is if the triangle is isoceles A = (1/2) b h
6 = (1/2) • 6 • h
6 = 3h ==>> h = 2
Pythagoras Theorem c2 = a2 + b2 ==>> Side2 = 32 + 22 draw it and you'll see
Side2 = 9 + 4 = 13
Side1 = sqrt(13)
So the sides of the triangle if it is isoceles are 6, sqrt(13), and sqrt(13)
The first easiest way is if the triangle is a right triangle and its two legs are 6 and 2.
If the triangle is neither isoceles nor a right triangle, then there isn't enough information
given to determine what its other two sides are.
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