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In triangle $ABC,$ $\angle C = 90^\circ.$ A semicircle is constructed along side $\overline{AC}$ that is tangent to $\overline{BC}$ and $\overline{AB}.$ If the radius of the semicircle is equal to BC, then find AC + BC + AB.

 
 Jun 11, 2024
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AB + AC + BC = 28

 Jun 13, 2024
edited by nathanl6656  Jun 13, 2024

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