Let $WXYZ$ be a trapezoid with bases $\overline{XY}$ and $\overline{WZ}$. In this trapezoid, $\angle ZXW = 120^\circ$, $\angle XWZ = 60^\circ$, and $\angle XYZ = 120^\circ$. Find $\angle YXZ$, in degrees.
Let's know that XZW will form a triangle
\(\angle ZXW = 90^\circ \\ \angle XWZ = 60^\circ\)
Thus, \(\angle XZW = 180 - 90 - 60 = 30\)
30 degrees is our answer.
Thanks! :)