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A circle is centered at (−8, −13)  and has a radius of 13.

What is the equation of the circle?

Enter the equation in the box using lower case variables x and y.

 May 23, 2018

Best Answer 

 #1
avatar+974 
+3

Hello lysxsa!

 

The standard equation for a circle with center (a,b) and radius of c is:

 

\((x-a)^2+(y-b)^2=r^2\)

 

Using this, we can create our equation necessary to answer the question. 

 

Since we already know the center and the radius, we can just plug in our values. 

 

\((x+8)^2+(y+13)^2=13^2=169\)

 

I hope this helped,

 

Gavin

 May 23, 2018
 #1
avatar+974 
+3
Best Answer

Hello lysxsa!

 

The standard equation for a circle with center (a,b) and radius of c is:

 

\((x-a)^2+(y-b)^2=r^2\)

 

Using this, we can create our equation necessary to answer the question. 

 

Since we already know the center and the radius, we can just plug in our values. 

 

\((x+8)^2+(y+13)^2=13^2=169\)

 

I hope this helped,

 

Gavin

GYanggg May 23, 2018
 #2
avatar+212 
+1

Thank you!

lysxsa  May 23, 2018

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