+212 A circle is centered at (−8, −13) and has a radius of 13.
What is the equation of the circle?
Enter the equation in the box using lower case variables x and y.
+981 Hello lysxsa!
The standard equation for a circle with center (a,b) and radius of c is:
\((x-a)^2+(y-b)^2=r^2\)
Using this, we can create our equation necessary to answer the question.
Since we already know the center and the radius, we can just plug in our values.
\((x+8)^2+(y+13)^2=13^2=169\)
I hope this helped,
Gavin
+981 Hello lysxsa!
The standard equation for a circle with center (a,b) and radius of c is:
\((x-a)^2+(y-b)^2=r^2\)
Using this, we can create our equation necessary to answer the question.
Since we already know the center and the radius, we can just plug in our values.
\((x+8)^2+(y+13)^2=13^2=169\)
I hope this helped,
Gavin
