A circle is centered at (−8, −13) and has a radius of 13.

What is the equation of the circle?

Enter the equation in the box using lower case variables x and y.

lysxsa
May 23, 2018

#1**+3 **

Hello lysxsa!

The standard equation for a circle with center (a,b) and radius of c is:

\((x-a)^2+(y-b)^2=r^2\)

Using this, we can create our equation necessary to answer the question.

Since we already know the center and the radius, we can just plug in our values.

\((x+8)^2+(y+13)^2=13^2=169\)

I hope this helped,

Gavin

GYanggg
May 23, 2018

#1**+3 **

Best Answer

Hello lysxsa!

The standard equation for a circle with center (a,b) and radius of c is:

\((x-a)^2+(y-b)^2=r^2\)

Using this, we can create our equation necessary to answer the question.

Since we already know the center and the radius, we can just plug in our values.

\((x+8)^2+(y+13)^2=13^2=169\)

I hope this helped,

Gavin

GYanggg
May 23, 2018