Get y alone.

y-3/x=0

I am assuming that you mean

y-(3/x)=0

Just add 3/x to both sides

y - 3/x + 3/x = 0 + 3/x

y = 3/x

Is that what you wanted?

what is 4 divided by x, subtract one

Melody:

y-3/x=0

I am assuming that you mean

y-(3/x)=0

Just add 3/x to both sides

y - 3/x + 3/x = 0 + 3/x

y = 3/x

Is that what you wanted?

Well, i discovered a problem, brackets aint in the problem when i got it... but its hard to write with the computer without brackets since it turns out wonrg... accroding to me

http://gyazo.com/407e19ed0fb481f0a7b1c4d8ebad4944

^^ Paint picture of the problem, amazing paint skills btw

Based on the picture all you have to do is multiply x on both sides.
Which would equal. y-3=x then you add 3
which gives you y=x+3.

y-3/x=0

Okay what you meant was
(y-3) / x = 0
The first thing that you need to recognise is that x cannot be equal to zero because you cannot divide by 0
then
multiply both sides by x and you get
y-3 = 0
so
y = 3 (where x is not equal to 0)

If you graphed this it would be a horizonal line through y=3 but there would be an open circle on (0,3) to show tht this point is not included.