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Given \(R(-6, 19)\) and \(S(15, -5)\) , what are the coordinates of the point on segment \(\overline{RS}\) two-thirds of the distance from R to S?

tertre  Dec 3, 2017

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'x' distance       2/3 x ( 15-(-6) ) = 14        14 + -6 = 8 = x

'y' distance       2/3 x (-5-19)  =  -16        19 - 16 = 3 = y

ElectricPavlov  Dec 3, 2017
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 #1
avatar+11300 
+1
Best Answer

'x' distance       2/3 x ( 15-(-6) ) = 14        14 + -6 = 8 = x

'y' distance       2/3 x (-5-19)  =  -16        19 - 16 = 3 = y

ElectricPavlov  Dec 3, 2017

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