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Given that $2^x = 7$, find the value of $4^{x-1}$.

 Feb 4, 2021
 #1
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2^x  = 7

 

4^(x  -1) =    4^x / 4  =  (2^2)^x / 4 = (2^x)^2  /4  = (7)^2/ 4  =  49/4

 

 

cool cool cool

 Feb 4, 2021
 #2
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omg thx so much cphil

 Feb 4, 2021

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