Given that (4, 5) and (-8, -4) are two points on a line, find the equation of the line and write your final answer in slope–intercept form.
The form we want is:
$${\mathtt{y}} = {\mathtt{mx}}{\mathtt{\,\small\textbf+\,}}{\mathtt{b}}$$
m = Δy/Δx
Δy = $$y_{2}$$-$$y_{1}$$
Δx = $$x_{2}$$-$$x_{1}$$
$${\mathtt{m}} = {\frac{\left({\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,-\,}}{\mathtt{5}}\right)}{\left({\mathtt{\,-\,}}{\mathtt{8}}{\mathtt{\,-\,}}{\mathtt{4}}\right)}}$$
So m = 0.75.
$${\mathtt{b}} = {\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{mx}}$$
We take one of the points and insert its coordinates into y and x.
b = 5 - 0.75 * 4 = 17
So the form is $${\mathtt{y}} = {\mathtt{0.75}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{17}}$$
We'll use y = mx + b
First, we need to find the slope, (m)........this is defined as ......the change in y / change in x
Look at (4, 5) and (-8, -4)
Note that, from the first point to the second, y changes by -9
And x changes by -12
So.....the slope is -9 / -12 = -3 / -4 = 3/4 = "m"
Now using either one of the points - i'll use the first one -we can substitute for y, m and x in y = mx + b to find "b"....so we have
5= (3/4)(4) + b simplify
5= 3 + b subtract 3 from both sides
b = 2
So our equation is
y = (3/4)x + 2
Check to see that the second point "works" in this equation.....just fill in for "x" and "y'
Does that help??
![]()
What's giving you trouble?? calculating the slope??.....or simplifying the equation??......something else??
![]()
That's the way math works sometimes......If you don't see it....you don't see it......then.......when you do see it....you wonder why you didn't see it in the first place !!!! LOL!!!
![]()