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Given that f(x)=(1/pi)^x, what is the range of f(x) on the interval [0,inf)?

Give your answer in interval notation.

 Jun 25, 2023
edited by HumenBeing  Jun 25, 2023
 #1
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The range of a function is the set of all possible outputs of the function. In this case, the function is f(x) = (1/pi)^x, and the interval is [0,inf).

As x increases, the value of (1/pi)^x decreases. This means that the range of f(x) on the interval [0,inf) is all numbers between 0 and 1, inclusive.

In other words, for any real number r in the range 0 <= r <= 1, there exists a value of x in the interval [0,inf) such that f(x) = r.  In interval notation, the range is [0,1].

 Jun 25, 2023
 #2
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HumenBeing is cheating again.

 Jun 25, 2023
 #3
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Yeah, HumenBeing cheats on a o p s hw and defends other cheaters

Guest Jun 25, 2023

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