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Given that the diagonals of a rhombus are always perpendicular bisectors of each other, what is the area of a rhombus with side length sqrt(10) units and diagonals that differ by 3 units?

 Nov 9, 2020
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Given that the diagonals of a rhombus are always perpendicular bisectors of each other, what is the area of a rhombus with side length sqrt(10) units and diagonals that differ by 3 units?

 

side   a = √10

 

1/2 of shorter diagonal   b = x

 

1/2 of longer diagonal    c = x + 1.5

 

a2 = b2 + c2                   10 = (x + 1.5)2 + x2              x = 1.356537443

 

I'll let you find the area of this rhombus.smiley

 Nov 9, 2020

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