Given that the diagonals of a rhombus are always perpendicular bisectors of each other, what is the area of a rhombus with side length sqrt(10) units and diagonals that differ by 3 units?
+1641 Given that the diagonals of a rhombus are always perpendicular bisectors of each other, what is the area of a rhombus with side length sqrt(10) units and diagonals that differ by 3 units?
side a = √10
1/2 of shorter diagonal b = x
1/2 of longer diagonal c = x + 1.5
a2 = b2 + c2 10 = (x + 1.5)2 + x2 x = 1.356537443
I'll let you find the area of this rhombus.
