Given that the points (16,-5) and (-40,16) lie on a line, what is the equation of the line? Explain.
(16,-5) and (-40,16)
We need to find the slope of this line, first...
This is gven by .... change in y / change in x = [16 - (-5)] / [-40 - 16 ] =
21 / -56 = -21/ 56 = -3/8
Now, using the slope-intercept form, we have
y + 5 = (-3/8)(x - 16)
y + 5 = (-3/8)x + 48/8
y = (-3/8)x + 6 - 5
y = (-3/8)x + 1
P.S....check this with the second set of points.....I believe you'll find that they work...
(16,-5) and (-40,16)
We need to find the slope of this line, first...
This is gven by .... change in y / change in x = [16 - (-5)] / [-40 - 16 ] =
21 / -56 = -21/ 56 = -3/8
Now, using the slope-intercept form, we have
y + 5 = (-3/8)(x - 16)
y + 5 = (-3/8)x + 48/8
y = (-3/8)x + 6 - 5
y = (-3/8)x + 1
P.S....check this with the second set of points.....I believe you'll find that they work...