Given the following function s(t)=3t^2-12t+15 for the displacement of an object, where s(t) is in metres and t is time in seconds, determine the displacement of the object when it is stationary.
+36916 When it is stationary, v = 0
If we take the derivative of the displacement fxn , it is the velocity function
then we can set the VELOCITY function = 0 to find TIME to substitute in to the DISPLACEMENT fxn
the derivative is
6t-12 = velocity
6t-12 = 0 yields t = 2 sec
Substitute this in to the displacement fxn
3(2^2) -12(2) +15 = 3 m
+36916 When it is stationary, v = 0
If we take the derivative of the displacement fxn , it is the velocity function
then we can set the VELOCITY function = 0 to find TIME to substitute in to the DISPLACEMENT fxn
the derivative is
6t-12 = velocity
6t-12 = 0 yields t = 2 sec
Substitute this in to the displacement fxn
3(2^2) -12(2) +15 = 3 m
