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# Given the following function s(t)=3t^2-12t+15 for the displacement of an object

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Given the following function s(t)=3t^2-12t+15 for the displacement of an object, where s(t) is in metres and t is time in seconds, determine the displacement of the object when it is stationary.

Nov 24, 2018

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When it is stationary, v = 0

If we take the derivative of the displacement fxn , it is the velocity function

then we can set the VELOCITY function = 0 to find TIME to substitute in to the DISPLACEMENT fxn

the derivative is

6t-12 = velocity

6t-12 = 0   yields t = 2 sec

Substitute this in to the displacement fxn

3(2^2) -12(2) +15 = 3 m

Nov 25, 2018

#1
0

When it is stationary, v = 0

If we take the derivative of the displacement fxn , it is the velocity function

then we can set the VELOCITY function = 0 to find TIME to substitute in to the DISPLACEMENT fxn

the derivative is

6t-12 = velocity

6t-12 = 0   yields t = 2 sec

Substitute this in to the displacement fxn

3(2^2) -12(2) +15 = 3 m

ElectricPavlov Nov 25, 2018