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Given the four digits 2, 4, 6, and 7, how many different positive three-digit integers can be formed using these digits if a digit may not be repeated in an integer?

 Nov 17, 2020
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4 P 3 = 4! = 24

 

{2, 4, 6} | {2, 4, 7} | {2, 6, 4} | {2, 6, 7} | {2, 7, 4} | {2, 7, 6} | {4, 2, 6} | {4, 2, 7} | {4, 6, 2} | {4, 6, 7} | {4, 7, 2} | {4, 7, 6} | {6, 2, 4} | {6, 2, 7} | {6, 4, 2} | {6, 4, 7} | {6, 7, 2} | {6, 7, 4} | {7, 2, 4} | {7, 2, 6} | {7, 4, 2} | {7, 4, 6} | {7, 6, 2} | {7, 6, 4} (total: 24)

 Nov 17, 2020

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