The problem is: f(x)=-4/x-9(-12)
[Its hard to tell what that equation really looks like, I wish I could make it to where it really looks like the real thing but its (-) and then 4 OVER x-9 kinda like a fraction and then -12
Example of a Domain and Range answer could be :
R,x≠{The Domain Number}
R,y≠{The Range Number}
I hope someone can EXPLAIN and UNDERSTAND what Im talking about, and Please give an answer
+23246 f(x) = 4/(x - 9) - 12
The domain is the set of all possible x-values; all x-values are legal except for 9 (which makes the denominator 0).
Every y-alue is possible except for -12 (you can't get -12 because: the only way that you can get -12 is for 4/(x - 9) to be 0 and you can't find an x-value that works.)
Another way to look at this: substitute y for f(x)
---> y = 4/(x - 9) - 12
Add 12 to both sides:
---> y + 12 = 4/(x - 9)
Multiply both sides by x - 9:
---> (x - 9)(y + 12) = 4
Neither x - 9 nor y + 12 can be 0 (if they were, the answer would be 0, not 4)
So, x can't be 9 and y can't be -12. (Anything else is OK.)
+23246 f(x) = 4/(x - 9) - 12
The domain is the set of all possible x-values; all x-values are legal except for 9 (which makes the denominator 0).
Every y-alue is possible except for -12 (you can't get -12 because: the only way that you can get -12 is for 4/(x - 9) to be 0 and you can't find an x-value that works.)
Another way to look at this: substitute y for f(x)
---> y = 4/(x - 9) - 12
Add 12 to both sides:
---> y + 12 = 4/(x - 9)
Multiply both sides by x - 9:
---> (x - 9)(y + 12) = 4
Neither x - 9 nor y + 12 can be 0 (if they were, the answer would be 0, not 4)
So, x can't be 9 and y can't be -12. (Anything else is OK.)
+128599 Here's the graph of what geno has described........https://www.desmos.com/calculator/pdlwkb21zg
Notice that we have asymptotes at y = -12 and at x = 9 .....just as geno predicted !!!!!
