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( x-4 ) ²= x²-16 Rechenweg pls
 Nov 20, 2012
 #1
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( x-4 ) ²= x²-16
( x-4 )^2= x^2-16
( x-4 )*( x-4 ) = x^2-16
x^2-8x+16 = x^2-16
| -x^2
x^2-8x+16-x^2 = x^2-16-x^2
x^2-8x+16-x^2 = -16
-8x+16 = -16
| -16
-8x+16-16 = -16-16
-8x = -32
| /-8
-8x = -32
x = 4

[input]( x-4 )^2= x^2-16[/input]
 Nov 20, 2012
 #2
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Hallelujah Danke!
 Nov 20, 2012

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