+0  
 
0
645
5
avatar+546 

sqrt-5 times sqrt5

cubed sqrt-5 times cubed sqrt-25

cubed sqrt9 times cubed sqrt-24

cubed sqrt-12 times cubed sqrt-18

sqrt50 times sqrt75

 Jul 14, 2014

Best Answer 

 #1
avatar+128578 
+10

1. √(-5)*√(-25)  = ( i √5 ) ( i √25 )  = i2 ( √5 ) (5 )  = -1 (5) √5  = - 5 √5

2. We can write this as......  (√-5))3 * ( √-25)3 =  ( i * √5))3 * ( i * √25)3 =

i6 ( √5 )3 * ( 5 )3   =  -1 (5√5) (125)  = -625√5  (remember Nataszaa..  i6 = i2 * i 2  * i 2 = -1 * -1 * -1 

= -1)

3.  (√9) 3 * √( -24) 3  = (3) 3 * ( i √(4 * 6) )3    =  27 i 3 (2 √6) 3   =  -27 i * 8 (√6) 3   = 216i (√6) 3  =

(216 i ) (6) (√6) =  1296 i √6  = 1296√6 i 

4.  (√-12) 3 * √( -18)  = i 3 * (2 √ 3) 3 * i 3 * (3  √ 2 ) 3  =  i 6 (8) (√3) 3 * (27) * (√2) 3  =

-1 (216) * (3)  * √3  * 2  * √2   =  -1296√6

5. √50 * √75 =  √(50*75) =  √(25 * 2 * 25 * 3) = 25 √6

 

  

 Jul 14, 2014
 #1
avatar+128578 
+10
Best Answer

1. √(-5)*√(-25)  = ( i √5 ) ( i √25 )  = i2 ( √5 ) (5 )  = -1 (5) √5  = - 5 √5

2. We can write this as......  (√-5))3 * ( √-25)3 =  ( i * √5))3 * ( i * √25)3 =

i6 ( √5 )3 * ( 5 )3   =  -1 (5√5) (125)  = -625√5  (remember Nataszaa..  i6 = i2 * i 2  * i 2 = -1 * -1 * -1 

= -1)

3.  (√9) 3 * √( -24) 3  = (3) 3 * ( i √(4 * 6) )3    =  27 i 3 (2 √6) 3   =  -27 i * 8 (√6) 3   = 216i (√6) 3  =

(216 i ) (6) (√6) =  1296 i √6  = 1296√6 i 

4.  (√-12) 3 * √( -18)  = i 3 * (2 √ 3) 3 * i 3 * (3  √ 2 ) 3  =  i 6 (8) (√3) 3 * (27) * (√2) 3  =

-1 (216) * (3)  * √3  * 2  * √2   =  -1296√6

5. √50 * √75 =  √(50*75) =  √(25 * 2 * 25 * 3) = 25 √6

 

  

CPhill Jul 14, 2014
 #2
avatar+546 
0

thank you! sorry for the urgency

 Jul 14, 2014
 #3
avatar+546 
0

hey CPhill!

My instructor said that this was "overthought"?

 Jul 16, 2014
 #4
avatar+1313 
0

What are you doing Nat that you like cubed numbers and irrationals a lot?"

Loling at CPhil reply. I've no idea about i yet. 

DOes i before a term have a different function to i after a term?

 Jul 16, 2014
 #6
avatar+546 
0

I am doing tutoring for Algebra 2! Needing extra help in some areas

 Jul 18, 2014

0 Online Users