Good Evening~

Let's find the inverse of both functions

y = 2x - 7  add 7 to both sides                             y= √(3x - 2)   square both sides

y + 7 = 2x     divide both sides by 2                     y^2  = 3x - 2   add 2 to both sides

(y + 7) / 2  = x     exchange x with y                   y^2 + 2 = 3x   divide both sides by 3

(x + 7) / 2  = y  = f^-1(x)                                     ( y^2 + 2) / 3  = x     exchange x and y

                                                                         (x^2 + 2 ) / 3  = y = g^-1(x)

And g^-1(5)   = (25 + 2) / 3 = 9

So   f^-1 (g^-1(5))  =  f^-1 (9) = (9 + 7) / 2  = 16 / 2 = 8

And f^-1 (-3) = ( -3 + 7) / 2  = 4 / 2 = 2

So g^-1 (f^-1(-3)) = g^-1 (2)  =  (2^2 + 2 ) / 3  = (6) / 3  = 2

Looks mind goggling. Thanks Chris