If anyone solves this without paper or a calculator and can prove it, you are literally the smartest person alive.
Consider the functions f(x)=√x and g(x)=7x+b. In the standard (x,y) coordinate plane, y=f(g(x)) passes through (4,6). What is the value of b?
This is actually my homework and I'm stumped, can anyone help?
+37099 b must equal 8
f(g(x)) = sq rt (7x+b)
substitute the point given (4,6) into the equation
y = sqrt(7(4)+b)
6 = sqrt(28 +b) Now, the sqrt of 36 = 6 so b must equal '8'
6 = sqrt(28+8)
6 = sqrt(36) = 6
+37099 b must equal 8
f(g(x)) = sq rt (7x+b)
substitute the point given (4,6) into the equation
y = sqrt(7(4)+b)
6 = sqrt(28 +b) Now, the sqrt of 36 = 6 so b must equal '8'
6 = sqrt(28+8)
6 = sqrt(36) = 6
