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I feel like I am missing something really obvious, but I don't understand

why the point  (3, 2π/5)  is not on the graph of  r = 3cos(5θ) .

 

If you plug in  2π/5  for  θ, you get  r = 3cos( 5(2π/5) )  =  3cos( 2π )  =  3(1)  =  3

 

So why isn't  (3, 2π/5)  a point on the graph?

 

*edit*

Okay....it looks like it is interpreting  (3, 2π/5)  as Cartesian coordinates, not as polar coordinates.

 Apr 25, 2019
edited by Guest  Apr 25, 2019
 #1
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Try this :  https://www.desmos.com/calculator/hohonscuef

 

 

cool cool cool

 Apr 25, 2019
 #2
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Thank you!!

 Apr 25, 2019

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