Graph the line that passes through the points. Then write an equation of the line in slope-intercept form.;

Graph the line that passes through the points. Then write an equation of the line in slope-intercept form.

(-5, 2), (2,4)

There are diffrerent ways to do this question but here is one way.

The gradient and y intercept form of a line is      y=mx+b

m is the gradient and b is the y intercept.  

If you look at this line it looks like it crosses the y axis at about 3.5 but this is unlikely to be exact so we do not have b yet.

The gradient =  $$\frac{rise}{run}=\frac{+2}{7}$$

so we have

$$\\y=mx+b\\ y=\frac{2}{7}x+b\\ $Now substitute in any point that you know lies on the line (2,4) will do.$\\ x=2,\;y=4\; 4=\frac{2}{7}*2+b\\ 4=\frac{4}{7}+b\\ 4-\frac{4}{7}=b\\ b=4-\frac{4}{7} b=3\frac{3}{7}=\frac{24}{7}\\\\ y=\frac{2}{7}x+\frac{24}{7}\\$$

i have no idea. when is the final exam due?

whenever. sooner is WAY BETTER because i have to finish Algebra 1.

this is a tough one. hmmmm. ill email it to melody, cphill, brittany, jay cole, and zegroes. lets see what they say