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Graph the quadratic function y=x^2-4x+2?

cHaRcOaL360  May 1, 2017
 #1
avatar+7089 
+3

This is one way of doing it.

 

We want to get the function into vertex form.

 

y = x2 - 4x + 2                  Subtract 2 from both sides.

y - 2 = x2 - 4x                   Add (-4/2)2 , or 4, to both sides.

y - 2 + 4 = x2 - 4x + 4       Now that the right hand side is a perfect square trinomial, factor it.

y + 2 = (x - 2)(x - 2)          

y + 2 = (x - 2)2                  Subtract 2 from both sides.

y = (x - 2)2 - 2

 

When the equation is in this form, we can see that this is the graph of y = x2 shifted to the right 2 units and shifted down 2 units. The vertex is at (2, -2). So plot the first point at (2, -2) and go up just like a basic parabola from there. :)

hectictar  May 1, 2017
 #2
avatar+92624 
+3

Using Desmos graphing calculator

 

https://www.desmos.com/calculator/xcpjkgigsm

 

Melody  May 1, 2017
 #3
avatar+12 
0

Thank you guys so much!!

cHaRcOaL360  May 2, 2017

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