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Graph z = 3cos315° + 3isin315° in the complex plane. How can I explain where I would find this equation on a complex plane?

 Mar 2, 2019
 #1
avatar+18840 
+2

You can just calculate it out to find the coordinates:

3 cos 315 = 2.12

3 i sin 315 = -2.12 i

plot    2.12 - 2.12 i     on the complex plane....

 Mar 2, 2019
 #2
avatar+102948 
+1

cos 315°   =   45° reference angle in the 4th quadrant =  √2 /2

 

And sin 315°    is the negative of this

 

So

 

z = (3) cos 315°  + ( 3i ) sin 315°  =

 

[   (3/2)√2  ,  - (3/2) √2 i  ]

 

Here is the graph

 

 

 

 

 

cool cool cool

 Mar 2, 2019

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