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The parabola y = ax^2 + bx + c is graphed below. Find a + b + c. (The grid lines are one unit apart.)
The parabola passes through (-2,8), (0,0), and (2,8).

 Jun 9, 2024
 #1
avatar+129733 
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The vertex is (0,0) = (h,k)

 

Using the vertex form  y =a(x -h)^2 + k  and (2,8)  we can  find "a"

 

8 = a (2 -0)^2  + 0

 

8 = 4a

 

a = 8/4 =  2

 

So

 

y = 2 (x)^2 + 0

 

y = 2x^2  

 

a = 2   b = 0    c = 0

 

a + b + c  =  2

 

cool cool cool

 Jun 9, 2024

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