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# Graphing/algebra question (time-sensitive)

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Find an equation for the LINE that satisfies the conditions:

#11 slope = 2/3; y intercept is 9

#12 slope = 7; y intercept is -3

#13 passes through (2, -1) and (0,1)

#14 passes through (2, 3) and (4,4)

can can somebody please explain this and maybe answer one or two so I can see how it works??

Jan 2, 2018

#1
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See if you can work out the first two from this:

And the second two from this:

Jan 2, 2018
#2
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#11 slope = 2/3; y intercept is 9

#12 slope = 7; y intercept is -3

#13 passes through (2, -1) and (0,1)

#14 passes through (2, 3) and (4,4)

I'll  do   11  and 13......try to do the other two.......12 is similar to 11  and  14 is similar to 13

11.....if the y intercept  is  9,  the point   (0,9)  is on the graph

So.....we have.....

y  =  (2/3)(x  -  0)  +  9

y  =  (2/3)x  +  9

13.....first.....find the slope  =

[subtract the y values in some order] /  [ subtract the x values in the same order ]

[ 1  -  -1  ]  /  [ 0  - 2 ]  =    2 / -2   = -1

So.....using the slope  and either of the points  - I'll use (0, 1) - we have

y  =  -1  (x  - 1)  +  0

y = -x + 1   Jan 2, 2018