how would i solve f[g(4pi^2)] using f(x)= sin^2 g(x)= square root of x
g(x) = sqrt x so g (4pi^2) = sqrt(4pi^2) = +-2pi
f(x) = sin^2 x so f(+- 2pi) = sin^2 (+-2pi)
= 0
+37084 
