I have a graphing problem that says 3x-y=1 I have the values for x but i don't know what y would be
okay, just say the values of x that you have are 0 and 2
When x = 0 you put 0 in for x and you get
3x-y=1
3*0 - y = 1
so
0 - y = 1
-y = 1
y = -1
So the point is x=0, y=-1 (0,-1)
When x=2 you substitute 2 for x and you get
3*2 - y = 1
6 - y = 1
-y = 1-6
-y = -5
y = 5
So the point is x=2, y=5 (2,5)
etc