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The x-intercetps of the parabola y = 2x^2 + 13x - 4 = 0 are at (p,0) and (q,0).  Find p and q.  Enter your answer in the form "p,q".

 Jun 23, 2021
 #1
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2x^2  +  13x   -  4   = 0

 

x^2  + (13/2) x  -  2  =  0      complete  the square

 

x^2  + (13/2)x  +  169 / 16   = 2 +  169 / 16

 

(x  +  13/4 )^2   =  201/16         yake  both roots

 

x +  13/4  =   ± sqrt (201)  / 4

 

p = - sqrt (201)/4  - 13/4          q =   sqrt (201) / 4  -  13  / 4

 

 

cool cool cool

 Jun 23, 2021

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