The x-intercetps of the parabola y = 2x^2 + 13x - 4 = 0 are at (p,0) and (q,0). Find p and q. Enter your answer in the form "p,q".
2x^2 + 13x - 4 = 0
x^2 + (13/2) x - 2 = 0 complete the square
x^2 + (13/2)x + 169 / 16 = 2 + 169 / 16
(x + 13/4 )^2 = 201/16 yake both roots
x + 13/4 = ± sqrt (201) / 4
p = - sqrt (201)/4 - 13/4 q = sqrt (201) / 4 - 13 / 4
