The graph of y = f(x) is a parabola whose vertex is at (1, -2). The graph of y = f(2x - 3) is also a parabola. Where is the vertex of the graph of y = f(2x-3)?
Let f(x) = (x - 1)^2 - 2
Then
f ( 2x - 3) = [ (2x - 3) - 1]^2 - 2 =
[ 2x - 4 ]^2 - 2 =
[ 2 ( x - 2)]^2 - 2 =
4 ( x - 2)^2 - 2
The vertex is ( 2 , -2)
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