The graph of y = ax^2 + bx + c is shown below. Find a times b times c. (The distance between the grid lines is one unit.)
+128474 The vertex is (3, 8) and the point (0, -1) is on the graph
So we have
-1 = a (0 = 3)^2 + 8 solve for "a'"
-1 = a ( 9 ) + 8
-1- 8 - a (9)
-9 = 9a
a = -1
The function is
y = -1 ( x - 3)*2 + 8
y = - 1 ( x^2 - 6x + 9) + 8
y = -x^2 + 6x - 9 + 8
y = -x^2 + 6x - 1
a = -1 b = 6 c = -1
abc = 6
