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The graph of y=ax^2+bx+c is given below, where a, b, and c are integers. Find a.

 

 Jun 30, 2022
 #1
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The roots are  x = -2  and x = 4  and the point (0,-8) is on the graph

 

So

 

-8 = a ( 0 + 2) ( 0 - 4)

 

-8 = -8a

 

a =1

 

So the function is

 

y = ( x +2)( x - 4)

 

y = x^2  - 2x  - 8

 

 

cool cool cool

 Jun 30, 2022

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