The graph of y=ax^2+bx+c is given below, where a, b, and c are integers. Find a.
The roots are x = -2 and x = 4 and the point (0,-8) is on the graph
So
-8 = a ( 0 + 2) ( 0 - 4)
-8 = -8a
a =1
So the function is
y = ( x +2)( x - 4)
y = x^2 - 2x - 8
