The equation y = (x + A)/(Bx + C), where A, B and C are integers, is shown below. What is A + B + C?
y = (x + A) / ( Bx + C)
(4,0) ---> 0 = (4 + A) / (B·4 + C)
0 = (4 + A) / (4B + C)
0 = 4 + A
A = -4
(0,-4) ---> -4 = (0 + A) / (B·0 + C)
-4 = A / C
-4 = -4 / C
C = 1
(-2,-2) ---> -2 = (-2 + A) / ( B·-2 + C)
-2 = (-2 + -4) / (-2B + 1)
-2 = -6 / (-2B + 1)
4B - 2 = -6
4B = -4
B = -1
y = (x + -4) / (-1X + 1)
You can calculate the final answer to the problem ...