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The graph of a certain quadratic y=ax2+bx+c is a parabola with vertex (4,0) which passes through the point (1,75). What is the value of a?

 Apr 13, 2021
 #1
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In  vertex  form  we  have  that

 

y  =a ( x + 4)^2  +  0

 

Since  ( 1, -75)  is  on the  graph, then

 

-75  = a ( 1 + 4)^2  +  0

 

-75  = a (5)^2

 

-75  = 25a

 

-75  / 25  =  a  =  - 3

 

 

cool cool cool

 Apr 13, 2021

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