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The graph of a certain quadratic y = ax^2 + bx + c is a parabola with vertex (-4,0) which passes through the point (7,1). What is the value of a?

 Jun 14, 2021
 #1
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ax^2  +  bx  +   c

 

Since  the vertex  is   (-4,0)   we have  a double root   at  x =  -4

 

So....the   equation becomes

 

y = a ( x + 4)^2....and     (7,1)  is on this graph....so....

 

1   = a ( 7 + 4)^2

 

1 =  a  *  11^2

 

1  =  121 a

 

a =   1/ 121

 

 

cool cool cool

 Jun 14, 2021

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