+168 Graph a sine function whose amplitude is 3, period is 4π , midline is y = 2, and y-intercept is (0,2) . The graph is not a reflection of the parent function over the x-axis.
Use the sine tool to graph the function.
The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.
Can someone help me graph this?
+129852 We have the form
y = Asin (Bx + C) + D
A= the amplitude = 3
B can be found as follows
B = 2pi / period = 2pi / 4pi = 1/2
C = phase shift.....there is none..so...C = 0
D = shift up/down.....the midline for the normal sine function would be y = 0
So....this is shifted up 2 units since the midline is y = 2
So....the function is
y = 3sin ( [ 1/2] x) + 2
Here's the graph :
