A and B are constants such that the graphs of xy = B and y = Ax^2 + B intersect at the point (2,8). Write the ordered pair (A,B).
Well
2*8 = B = 16
And
y =Ax^2 + B .....so....
8 = A(2)^2 + 16
-8 = 4A
A = -8/4 = -2
(A,B) = (-2, 16)
