I don't know if you can help me with this here, but I need help figuring out how to graph this trig function.
The function is: $$y = 2 + 3 sin \frac{1}{2}(x-pi)$$
$$y = 2 + 3 sin \frac{1}{2}(x-pi)$$
Let's take this by parts........
The "2" shifts the basic sine graph "up" 2 units.
The "3" increases the amplitude of the basic graph by a factor of 3
Using the "1/2" we can find the period of the function, thusly:
(1/2)x = 2pi solving for x gives us the period
x = 4pi ..... so the "1/2" doubles the period of the normal sine function
The (x - pi) shits the graph to the right by "pi" units
Here are the graphs of the normal sine function and our function on the same axis
Hope that helps some.......