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I don't know if you can help me with this here, but I need help figuring out how to graph this trig function. 

 

The function is: $$y = 2 + 3 sin \frac{1}{2}(x-pi)$$

 May 30, 2014
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$$y = 2 + 3 sin \frac{1}{2}(x-pi)$$

Let's take this by parts........

The "2" shifts the basic sine graph "up" 2 units.

The "3" increases the amplitude of the basic graph by a factor of 3

Using the "1/2" we can find the period of the function, thusly:

(1/2)x = 2pi       solving for x gives us the period

x = 4pi    ..... so the "1/2" doubles the period of the normal sine function

The (x - pi)  shits the graph to the right by "pi" units

Here are the graphs of the normal sine function and our function on the same axis

 

 

 Hope that helps some.......

 May 30, 2014

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