On the graph of y = (x + 2)^2 - 10, how many points are there whose coordinates are both negative integers?
+2165
On the graph of y = (x + 2)^2 - 10, how many points are there whose coordinates are both negative integers?
y = (x + 2)2 – 10
Considering only integers, it's obvious that when x < –6
then y goes positive, so with so few let's just try them all.
when x = –1, y = –9
when x = –2, y = –10
when x = –3, y = –9
when x = –4, y = –6
when x = –5, y = –1 so there are five such points.
.
