The graph of the equation y = Ax^2 + Bx + C , where are A, B, C integers, is shown below. Find A + B + C.
Vertex form ( vertex is at -1,-1)
y =a (x+1)^2 - 1 find a convenient integer point (not the vertex) on the graph to calculate the value of 'a' (0,0 is a good one)
0 = a (1) -1 so a = 1
y = (x+1) ^2 -1 expand to get the requested form
y = x^2 + 2x +1 - 1
y = x^2 + 2x + 0 take it from here ....