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The graph of the equation y = Ax^2 + Bx + C , where are A, B, C integers, is shown below. Find A + B + C.

 

 May 12, 2021
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Vertex form   ( vertex is at -1,-1)

y =a (x+1)^2 - 1      find a convenient integer point (not the vertex) on the graph to calculate the value of 'a'  (0,0 is a good one)

0 = a (1) -1            so a = 1

 

y = (x+1) ^2 -1      expand to get the requested form

y = x^2 + 2x +1 - 1

y = x^2 + 2x + 0       take it from here ....

 May 12, 2021
edited by ElectricPavlov  May 12, 2021

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